Optimal. Leaf size=260 \[ -\frac{2 \sin ^5(c+d x) \cos (c+d x)}{11 a^2 d \sqrt{a \sin (c+d x)+a}}+\frac{46 \sin ^4(c+d x) \cos (c+d x)}{99 a^2 d \sqrt{a \sin (c+d x)+a}}-\frac{424 \sin ^3(c+d x) \cos (c+d x)}{693 a^2 d \sqrt{a \sin (c+d x)+a}}+\frac{200 \sin ^2(c+d x) \cos (c+d x)}{231 a^2 d \sqrt{a \sin (c+d x)+a}}-\frac{1048 \cos (c+d x) \sqrt{a \sin (c+d x)+a}}{693 a^3 d}+\frac{4496 \cos (c+d x)}{693 a^2 d \sqrt{a \sin (c+d x)+a}}-\frac{4 \sqrt{2} \tanh ^{-1}\left (\frac{\sqrt{a} \cos (c+d x)}{\sqrt{2} \sqrt{a \sin (c+d x)+a}}\right )}{a^{5/2} d} \]
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Rubi [A] time = 1.35904, antiderivative size = 260, normalized size of antiderivative = 1., number of steps used = 18, number of rules used = 9, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.29, Rules used = {2880, 2778, 2983, 2968, 3023, 2751, 2649, 206, 3046} \[ -\frac{2 \sin ^5(c+d x) \cos (c+d x)}{11 a^2 d \sqrt{a \sin (c+d x)+a}}+\frac{46 \sin ^4(c+d x) \cos (c+d x)}{99 a^2 d \sqrt{a \sin (c+d x)+a}}-\frac{424 \sin ^3(c+d x) \cos (c+d x)}{693 a^2 d \sqrt{a \sin (c+d x)+a}}+\frac{200 \sin ^2(c+d x) \cos (c+d x)}{231 a^2 d \sqrt{a \sin (c+d x)+a}}-\frac{1048 \cos (c+d x) \sqrt{a \sin (c+d x)+a}}{693 a^3 d}+\frac{4496 \cos (c+d x)}{693 a^2 d \sqrt{a \sin (c+d x)+a}}-\frac{4 \sqrt{2} \tanh ^{-1}\left (\frac{\sqrt{a} \cos (c+d x)}{\sqrt{2} \sqrt{a \sin (c+d x)+a}}\right )}{a^{5/2} d} \]
Antiderivative was successfully verified.
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Rule 2880
Rule 2778
Rule 2983
Rule 2968
Rule 3023
Rule 2751
Rule 2649
Rule 206
Rule 3046
Rubi steps
\begin{align*} \int \frac{\cos ^4(c+d x) \sin ^4(c+d x)}{(a+a \sin (c+d x))^{5/2}} \, dx &=\frac{\int \frac{\sin ^4(c+d x) \left (1+\sin ^2(c+d x)\right )}{\sqrt{a+a \sin (c+d x)}} \, dx}{a^2}-\frac{2 \int \frac{\sin ^5(c+d x)}{\sqrt{a+a \sin (c+d x)}} \, dx}{a^2}\\ &=\frac{4 \cos (c+d x) \sin ^4(c+d x)}{9 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{2 \cos (c+d x) \sin ^5(c+d x)}{11 a^2 d \sqrt{a+a \sin (c+d x)}}+\frac{2 \int \frac{\sin ^4(c+d x) \left (\frac{21 a}{2}-\frac{1}{2} a \sin (c+d x)\right )}{\sqrt{a+a \sin (c+d x)}} \, dx}{11 a^3}+\frac{2 \int \frac{\sin ^3(c+d x) (-8 a+a \sin (c+d x))}{\sqrt{a+a \sin (c+d x)}} \, dx}{9 a^3}\\ &=-\frac{4 \cos (c+d x) \sin ^3(c+d x)}{63 a^2 d \sqrt{a+a \sin (c+d x)}}+\frac{46 \cos (c+d x) \sin ^4(c+d x)}{99 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{2 \cos (c+d x) \sin ^5(c+d x)}{11 a^2 d \sqrt{a+a \sin (c+d x)}}+\frac{4 \int \frac{\sin ^3(c+d x) \left (-2 a^2+\frac{95}{2} a^2 \sin (c+d x)\right )}{\sqrt{a+a \sin (c+d x)}} \, dx}{99 a^4}+\frac{4 \int \frac{\sin ^2(c+d x) \left (3 a^2-\frac{57}{2} a^2 \sin (c+d x)\right )}{\sqrt{a+a \sin (c+d x)}} \, dx}{63 a^4}\\ &=\frac{76 \cos (c+d x) \sin ^2(c+d x)}{105 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{424 \cos (c+d x) \sin ^3(c+d x)}{693 a^2 d \sqrt{a+a \sin (c+d x)}}+\frac{46 \cos (c+d x) \sin ^4(c+d x)}{99 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{2 \cos (c+d x) \sin ^5(c+d x)}{11 a^2 d \sqrt{a+a \sin (c+d x)}}+\frac{8 \int \frac{\sin ^2(c+d x) \left (\frac{285 a^3}{2}-\frac{123}{4} a^3 \sin (c+d x)\right )}{\sqrt{a+a \sin (c+d x)}} \, dx}{693 a^5}+\frac{8 \int \frac{\sin (c+d x) \left (-57 a^3+\frac{87}{4} a^3 \sin (c+d x)\right )}{\sqrt{a+a \sin (c+d x)}} \, dx}{315 a^5}\\ &=\frac{200 \cos (c+d x) \sin ^2(c+d x)}{231 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{424 \cos (c+d x) \sin ^3(c+d x)}{693 a^2 d \sqrt{a+a \sin (c+d x)}}+\frac{46 \cos (c+d x) \sin ^4(c+d x)}{99 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{2 \cos (c+d x) \sin ^5(c+d x)}{11 a^2 d \sqrt{a+a \sin (c+d x)}}+\frac{16 \int \frac{\sin (c+d x) \left (-\frac{123 a^4}{2}+\frac{2973}{8} a^4 \sin (c+d x)\right )}{\sqrt{a+a \sin (c+d x)}} \, dx}{3465 a^6}+\frac{8 \int \frac{-57 a^3 \sin (c+d x)+\frac{87}{4} a^3 \sin ^2(c+d x)}{\sqrt{a+a \sin (c+d x)}} \, dx}{315 a^5}\\ &=\frac{200 \cos (c+d x) \sin ^2(c+d x)}{231 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{424 \cos (c+d x) \sin ^3(c+d x)}{693 a^2 d \sqrt{a+a \sin (c+d x)}}+\frac{46 \cos (c+d x) \sin ^4(c+d x)}{99 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{2 \cos (c+d x) \sin ^5(c+d x)}{11 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{116 \cos (c+d x) \sqrt{a+a \sin (c+d x)}}{315 a^3 d}+\frac{16 \int \frac{-\frac{123}{2} a^4 \sin (c+d x)+\frac{2973}{8} a^4 \sin ^2(c+d x)}{\sqrt{a+a \sin (c+d x)}} \, dx}{3465 a^6}+\frac{16 \int \frac{\frac{87 a^4}{8}-\frac{429}{4} a^4 \sin (c+d x)}{\sqrt{a+a \sin (c+d x)}} \, dx}{945 a^6}\\ &=\frac{1144 \cos (c+d x)}{315 a^2 d \sqrt{a+a \sin (c+d x)}}+\frac{200 \cos (c+d x) \sin ^2(c+d x)}{231 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{424 \cos (c+d x) \sin ^3(c+d x)}{693 a^2 d \sqrt{a+a \sin (c+d x)}}+\frac{46 \cos (c+d x) \sin ^4(c+d x)}{99 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{2 \cos (c+d x) \sin ^5(c+d x)}{11 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{1048 \cos (c+d x) \sqrt{a+a \sin (c+d x)}}{693 a^3 d}+\frac{32 \int \frac{\frac{2973 a^5}{16}-\frac{3711}{8} a^5 \sin (c+d x)}{\sqrt{a+a \sin (c+d x)}} \, dx}{10395 a^7}+\frac{2 \int \frac{1}{\sqrt{a+a \sin (c+d x)}} \, dx}{a^2}\\ &=\frac{4496 \cos (c+d x)}{693 a^2 d \sqrt{a+a \sin (c+d x)}}+\frac{200 \cos (c+d x) \sin ^2(c+d x)}{231 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{424 \cos (c+d x) \sin ^3(c+d x)}{693 a^2 d \sqrt{a+a \sin (c+d x)}}+\frac{46 \cos (c+d x) \sin ^4(c+d x)}{99 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{2 \cos (c+d x) \sin ^5(c+d x)}{11 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{1048 \cos (c+d x) \sqrt{a+a \sin (c+d x)}}{693 a^3 d}+\frac{2 \int \frac{1}{\sqrt{a+a \sin (c+d x)}} \, dx}{a^2}-\frac{4 \operatorname{Subst}\left (\int \frac{1}{2 a-x^2} \, dx,x,\frac{a \cos (c+d x)}{\sqrt{a+a \sin (c+d x)}}\right )}{a^2 d}\\ &=-\frac{2 \sqrt{2} \tanh ^{-1}\left (\frac{\sqrt{a} \cos (c+d x)}{\sqrt{2} \sqrt{a+a \sin (c+d x)}}\right )}{a^{5/2} d}+\frac{4496 \cos (c+d x)}{693 a^2 d \sqrt{a+a \sin (c+d x)}}+\frac{200 \cos (c+d x) \sin ^2(c+d x)}{231 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{424 \cos (c+d x) \sin ^3(c+d x)}{693 a^2 d \sqrt{a+a \sin (c+d x)}}+\frac{46 \cos (c+d x) \sin ^4(c+d x)}{99 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{2 \cos (c+d x) \sin ^5(c+d x)}{11 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{1048 \cos (c+d x) \sqrt{a+a \sin (c+d x)}}{693 a^3 d}-\frac{4 \operatorname{Subst}\left (\int \frac{1}{2 a-x^2} \, dx,x,\frac{a \cos (c+d x)}{\sqrt{a+a \sin (c+d x)}}\right )}{a^2 d}\\ &=-\frac{4 \sqrt{2} \tanh ^{-1}\left (\frac{\sqrt{a} \cos (c+d x)}{\sqrt{2} \sqrt{a+a \sin (c+d x)}}\right )}{a^{5/2} d}+\frac{4496 \cos (c+d x)}{693 a^2 d \sqrt{a+a \sin (c+d x)}}+\frac{200 \cos (c+d x) \sin ^2(c+d x)}{231 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{424 \cos (c+d x) \sin ^3(c+d x)}{693 a^2 d \sqrt{a+a \sin (c+d x)}}+\frac{46 \cos (c+d x) \sin ^4(c+d x)}{99 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{2 \cos (c+d x) \sin ^5(c+d x)}{11 a^2 d \sqrt{a+a \sin (c+d x)}}-\frac{1048 \cos (c+d x) \sqrt{a+a \sin (c+d x)}}{693 a^3 d}\\ \end{align*}
Mathematica [C] time = 1.05643, size = 224, normalized size = 0.86 \[ \frac{\left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )^5 \left (-73458 \sin \left (\frac{1}{2} (c+d x)\right )-15246 \sin \left (\frac{3}{2} (c+d x)\right )+4851 \sin \left (\frac{5}{2} (c+d x)\right )+1485 \sin \left (\frac{7}{2} (c+d x)\right )-385 \sin \left (\frac{9}{2} (c+d x)\right )-63 \sin \left (\frac{11}{2} (c+d x)\right )+73458 \cos \left (\frac{1}{2} (c+d x)\right )-15246 \cos \left (\frac{3}{2} (c+d x)\right )-4851 \cos \left (\frac{5}{2} (c+d x)\right )+1485 \cos \left (\frac{7}{2} (c+d x)\right )+385 \cos \left (\frac{9}{2} (c+d x)\right )-63 \cos \left (\frac{11}{2} (c+d x)\right )+(88704+88704 i) (-1)^{3/4} \tanh ^{-1}\left (\left (\frac{1}{2}+\frac{i}{2}\right ) (-1)^{3/4} \left (\tan \left (\frac{1}{4} (c+d x)\right )-1\right )\right )\right )}{11088 d (a (\sin (c+d x)+1))^{5/2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 1.031, size = 166, normalized size = 0.6 \begin{align*} -{\frac{2+2\,\sin \left ( dx+c \right ) }{693\,{a}^{8}\cos \left ( dx+c \right ) d}\sqrt{-a \left ( \sin \left ( dx+c \right ) -1 \right ) } \left ( 1386\,{a}^{11/2}\sqrt{2}{\it Artanh} \left ( 1/2\,{\frac{\sqrt{a-a\sin \left ( dx+c \right ) }\sqrt{2}}{\sqrt{a}}} \right ) -63\, \left ( a-a\sin \left ( dx+c \right ) \right ) ^{11/2}+154\,a \left ( a-a\sin \left ( dx+c \right ) \right ) ^{9/2}-198\,{a}^{2} \left ( a-a\sin \left ( dx+c \right ) \right ) ^{7/2}-231\,{a}^{4} \left ( a-a\sin \left ( dx+c \right ) \right ) ^{3/2}-1386\,{a}^{5}\sqrt{a-a\sin \left ( dx+c \right ) } \right ){\frac{1}{\sqrt{a+a\sin \left ( dx+c \right ) }}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cos \left (d x + c\right )^{4} \sin \left (d x + c\right )^{4}}{{\left (a \sin \left (d x + c\right ) + a\right )}^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.19554, size = 846, normalized size = 3.25 \begin{align*} \frac{2 \,{\left (\frac{693 \, \sqrt{2}{\left (a \cos \left (d x + c\right ) + a \sin \left (d x + c\right ) + a\right )} \log \left (-\frac{\cos \left (d x + c\right )^{2} -{\left (\cos \left (d x + c\right ) - 2\right )} \sin \left (d x + c\right ) - \frac{2 \, \sqrt{2} \sqrt{a \sin \left (d x + c\right ) + a}{\left (\cos \left (d x + c\right ) - \sin \left (d x + c\right ) + 1\right )}}{\sqrt{a}} + 3 \, \cos \left (d x + c\right ) + 2}{\cos \left (d x + c\right )^{2} -{\left (\cos \left (d x + c\right ) + 2\right )} \sin \left (d x + c\right ) - \cos \left (d x + c\right ) - 2}\right )}{\sqrt{a}} -{\left (63 \, \cos \left (d x + c\right )^{6} - 161 \, \cos \left (d x + c\right )^{5} - 562 \, \cos \left (d x + c\right )^{4} + 622 \, \cos \left (d x + c\right )^{3} + 1759 \, \cos \left (d x + c\right )^{2} +{\left (63 \, \cos \left (d x + c\right )^{5} + 224 \, \cos \left (d x + c\right )^{4} - 338 \, \cos \left (d x + c\right )^{3} - 960 \, \cos \left (d x + c\right )^{2} + 799 \, \cos \left (d x + c\right ) + 2984\right )} \sin \left (d x + c\right ) - 2185 \, \cos \left (d x + c\right ) - 2984\right )} \sqrt{a \sin \left (d x + c\right ) + a}\right )}}{693 \,{\left (a^{3} d \cos \left (d x + c\right ) + a^{3} d \sin \left (d x + c\right ) + a^{3} d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 2.67354, size = 637, normalized size = 2.45 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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